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21.合并两个有序链表.js
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21.合并两个有序链表.js
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/*
* @lc app=leetcode.cn id=21 lang=javascript
*
* [21] 合并两个有序链表
*
* https://leetcode-cn.com/problems/merge-two-sorted-lists/description/
*
* algorithms
* Easy (53.90%)
* Total Accepted: 61.1K
* Total Submissions: 113.3K
* Testcase Example: '[1,2,4]\n[1,3,4]'
*
* 将两个有序链表合并为一个新的有序链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。
*
* 示例:
*
* 输入:1->2->4, 1->3->4
* 输出:1->1->2->3->4->4
*
*
*/
/**
* Definition for singly-linked list.
* function ListNode(val) {
* this.val = val;
* this.next = null;
* }
*/
/**
* @param {ListNode} l1
* @param {ListNode} l2
* @return {ListNode}
*/
var mergeTwoLists = function(l1, l2) {
const newList = new Object()
if (l1 && l2) {
if (l1.val > l2.val) {
newList.val = l2.val
newList.next = mergeTwoLists(l1, l2.next)
} else {
newList.val = l1.val
newList.next = mergeTwoLists(l1.next, l2)
}
} else if (l1) {
newList.val = l1.val
newList.next = l1.next
} else if (l2) {
newList.val = l2.val
newList.next = l2.next
} else return null
return newList
}