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59_ft_digit_split.c
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59_ft_digit_split.c
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/*
Write the function ft_digit_split that will take a string as an argument
It must return an array of integers, where every element will be the integer represented by the corresponding character of its argument
If the string contains a non digit character, return a NULL pointer
You cannot have any memory leaks!
The function must be prototyped as follows: int *ft_digit_split(char *str);
Example:
ft_digit_split("0123"); // will return the following array: [0 , 1 , 2 , 3]
ft_digit_split("abc"); // will return NULL
Allowed functions: malloc, free
*/
#include <stdlib.h>
#include <stdio.h>
int non_digit(char *str)
{
int i;
i = 0;
while (str[i])
{
if ((str[i] < '0' || str[i] > '9'))
{
return (0);
}
i++;
}
return (1);
}
int ft_strlen(char *str)
{
int i;
i = 0;
while (str[i])
i++;
return (i);
}
int *ft_digit_split(char *str)
{
int i;
i = 0;
int *array;
if ((non_digit(str)) == 0)
{
return (0);
}
array = malloc(ft_strlen(str) * sizeof(int));
while (i < ft_strlen(str))
{
array[i] = str[i] - 48; // - 48(char '0') to convert ascii to int
i++;
}
return (array);
}
int main()
{
int i;
i = 0;
char *str = "123";
int str_len;
str_len = ft_strlen(str);
int *array;
array = ft_digit_split(str);
if (!array)
printf("NULL\n");
else
{
while (i < str_len)
{
printf("[%d]", array[i]);
i++;
}
}
printf("\n");
return (0);
}