$ cat /proc/cpuinfo | grep name | sort | uniq
model name : Intel(R) Xeon(R) CPU E5-2630 v3 @ 2.40GHz
$ cat /proc/cpuinfo | grep "physical id"
physical id : 0
physical id : 1
physical id : 0
physical id : 1
physical id : 0
physical id : 1
physical id : 0
physical id : 1
physical id : 0
physical id : 1
physical id : 0
physical id : 1
physical id : 0
physical id : 1
physical id : 0
physical id : 1
physical id : 0
physical id : 1
physical id : 0
physical id : 1
physical id : 0
physical id : 1
physical id : 0
physical id : 1
physical id : 0
physical id : 1
physical id : 0
physical id : 1
physical id : 0
physical id : 1
physical id : 0
physical id : 1
所有physical id都是0,可知有1个物理CPU。这里有0又有1所以是两个物理cpu。
也用管道排序去重后直接输出物理cpu的个数;
$ cat /proc/cpuinfo | grep "physical id" | sort | uniq | wc -l
2
$ cat /proc/cpuinfo | grep "core id" | sort | uniq | wc -l
8
$ cat /proc/cpuinfo | grep "processor" | sort | uniq | wc -l
32
由图可知:2颗物理CPU,8核32线程;
$ lscpu
Architecture: x86_64
CPU op-mode(s): 32-bit, 64-bit
Byte Order: Little Endian
CPU(s): 32
On-line CPU(s) list: 0-31
Thread(s) per core: 2
Core(s) per socket: 8
Socket(s): 2
NUMA node(s): 2
Vendor ID: GenuineIntel
CPU family: 6
Model: 63
Stepping: 2
CPU MHz: 2400.001
BogoMIPS: 4799.30
Virtualization: VT-x
L1d cache: 32K
L1i cache: 32K
L2 cache: 256K
L3 cache: 20480K
NUMA node0 CPU(s): 0,2,4,6,8,10,12,14,16,18,20,22,24,26,28,30
NUMA node1 CPU(s): 1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31
主要是看下面几个
CPU(s): 32 #32个逻辑cpu
Thread(s) per core: 2
Core(s) per socket: 8
Socket(s): 2 #2个物理cpu