A good meal is a meal that contains exactly two different food items with a sum of deliciousness equal to a power of two.
You can pick any two different foods to make a good meal.
Given an array of integers deliciousness
where deliciousness[i]
is the deliciousness of the ith
item of food, return the number of different good meals you can make from this list modulo 109 + 7
.
Note that items with different indices are considered different even if they have the same deliciousness value.
Example 1:
Input: deliciousness = [1,3,5,7,9] Output: 4 Explanation: The good meals are (1,3), (1,7), (3,5) and, (7,9). Their respective sums are 4, 8, 8, and 16, all of which are powers of 2.
Example 2:
Input: deliciousness = [1,1,1,3,3,3,7] Output: 15 Explanation: The good meals are (1,1) with 3 ways, (1,3) with 9 ways, and (1,7) with 3 ways.
Constraints:
1 <= deliciousness.length <= 105
0 <= deliciousness[i] <= 220
class Solution:
def countPairs(self, deliciousness: List[int]) -> int:
mod = 1000000007
limit = max(deliciousness) * 2
pairs = 0
freq = collections.defaultdict(int)
for d in deliciousness:
target = 1
while target <= limit:
pairs = (pairs + freq[target - d]) % mod
target = target << 1
freq[d] += 1
return pairs
class Solution {
private static final int MOD = 1000000007;
public int countPairs(int[] deliciousness) {
int limit = Arrays.stream(deliciousness).max().getAsInt() * 2;
int pairs = 0;
Map<Integer, Integer> freq = new HashMap<>();
for (int d : deliciousness) {
for (int sum = 1; sum <= limit; sum <<= 1) {
int count = freq.getOrDefault(sum - d, 0);
pairs = (pairs + count) % MOD;
}
freq.merge(d, 1, Integer::sum);
}
return pairs;
}
}
const mod int = 1e9 + 7
func countPairs(deliciousness []int) int {
limit := 0
for _, d := range deliciousness {
limit = max(limit, d)
}
limit *= 2
pairs := 0
freq := make(map[int]int)
for _, d := range deliciousness {
for sum := 1; sum <= limit; sum <<= 1 {
pairs = (pairs + freq[sum-d]) % mod
}
freq[d]++
}
return pairs
}
func max(x, y int) int {
if x > y {
return x
}
return y
}