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isDays.txt
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#<python代码：判断输入的日期是该年的第几天>
#def isDays(year,month,day):
# months = [31,0,31,30,31,30,31,31,30,31,30,31]
# sum = 0
# if (year % 400 ==0) or (year % 100 !=0 and year % 4 == 0):
# months[1] = 29
# else:
# months[1] = 28
# for i in range(0,month-1,1):
# sum += months[i]
# sum += day
# print("days:",sum)
##isDays(2018,5,5) #125
#isDays(2006,1,12) #71
#<汇编代码：判断输入的日期是该年的第几天>
move R15,10000
move sp,R15
move R2,2006 #R2表示年
move R3,1 #R3表示月
move R4,12 #R4表示日
push R4
push R3
push R2
call LisDays
goto Lprint
LisDays:
push R15
move R15,sp
push R2
push R3
push R4
push R5
push R6
push R7
push R14
_data 1,[31,0,31,30,31,30,31,31,30,31,30,31]
move R14,1 #R14表示序列的首地址
load R2,02(R15) #获取到年的值
#year % 400
div R5,R2,400
mul R5,R5,400
sub R5,R2,R5 #R7表示year % 400的值
beqz R5,L0
move R5,0 #R7表示year % 400 ==0的真值
goto Lyear100
L0:
move R5,1 #R7表示year % 400 ==0的真值
Lyear100:
#year % 100
div R6,R2,100
mul R6,R6,100
sub R6,R2,R6
beqz R6,L1
move R6,1
goto Lyear4
L1:
move R6,0
Lyear4:
#year % 4
div R7,R2,4
mul R7,R7,4
sub R7,R2,R7
beqz R7,L2
move R7,0
goto Lconditions
L2:
move R7,1
Lconditions:
and R7,R6,R7
or R7,R5,R7
beqz R7,L28
L29:
move R7,29
store 01(R14),R7 #设置months[1]的值
goto Lfor
L28:
move R7,28
store 01(R14),R7 #设置months[1]的值
Lfor:
sub R3, R3, 1
sle R2,R3,0
beqz R2, Lday
add R1, R1, R4
goto Lreturn
Lday:
load R2,00(R3) #如果首地址变了不是1，只需要在之前完成一次加首地址的操作即可,比如add R3,R3,基地址
add R1, R1, R2
goto Lfor
Lreturn:
pop R14
pop R7
pop R6
pop R5
pop R4
pop R3
pop R2
move sp,R15
pop R15
ret
Lprint:
_pr "days:",R1