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RegEx

Links

Usage

See https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/search

'str'.search(/pattern/) // returns index
/pattern/.test('str') // : boolean
/pattern/.exec('str') // return null or matches array ([0] is full string, [1].. is group

Checklist

  • Be careful about the greedy matching .*, try to add ? to use lazy matching: .*?. See here
  • Positive lookahead (does incldue): (?=...)
  • Negative lookahead (not include multiple chars): (?!...)
    • to match a single char that's not in the list, you can use [^abc] (means match one char that's not a or b or c)
  • Positive lookbehind: (?<=...) NOTE JavaScript doens't have this. You can use negative lookahead

Examples

How to replace "name" : "basic" to "xxx" : "whatever you provided"?

using grouping for everything: http://stackoverflow.com/a/6005637/166286

// c#
string input = "'name' : 'Basic'," ;
string find = "('name'\\s:\\s')(?<text>.*)(')" ;
string replace = "$1AA$2" ;
string result = Regex.Replace (input, find, replace);
Console.WriteLine(result);

Find the number after a certain word:

(?<=%download%#)\d+

The lookbehind assertion (?<=foo_bar) is important because you don't want to include %download%# in your results, only the numbers after it.
http://stackoverflow.com/questions/4740984/c-sharp-regex-matches-example

How to make sure string 'po box' is not in the test string:

Use negative lookahead: /^(?!.*po\sBOX).*$/

How to find a pattern before a word:

Let's say we want to match and replace :user in the url abc.com/:user/notebooks/:user-name/:userName
Use We could use: /:user(?=\b)/, which will match the first :user and :user-name but not :userName.

Split using a maximum length (Ruby)

regex = /.{1,#{max_width}}/
text.scan(regex).join(zero_width_space)

Match string insdie single quotes

https://regex101.com/r/uH6uK3/1

var result = [];
const pattern = /'([^',]+)'/g;
var match;
while(match = pattern.exec("'a','b', 'c'")) {
    result.push(match[1]);
}
console.log(result);

match a word

  • use word boundary: \b
  • be sure to be lazy (+?)
const re = /^\/(.+?)\b/;
re.exec('/abc/def')[1] // -> abc
re.exec('/abc-def')[1] // -> abc
re.exec('/abc_def')[1] // -> abc_def