Is there a way to parse expression with functions in them?

[magdalini-anastasiadou]

Hello!
I was wondering if there is a way to parse expressions with functions using parse_expression.
Here is a sample code explaining what I mean.

import pint

ureg = pint.UnitRegistry()
text = "pow(2, 3) * m/s"
parsed = ureg.parse_expression(text)

Initially, I thought that since we can pass keyworded arguments in parse_expression it would work with methods too, but this isn't the case. So I am searching for a different way.

Btw with keyworded arguments I mean this
parsed = ureg.parse_expression("x+2", x=2)

Also, I see there is a way to define methods using wrapping but pint isn't aware of the defined ones when it parses the expression.

So in conclusion, is there a way to do it?

Thanks :)

[hgrecco]

Pint only parses unary and binary operators, and a few selected things (squared, cubed) through replacements. It allows you to write a custom replacement rule should you like to write a textual transformation every single time.

Regarding keyword arguments, pint does not support that.