version 0.5.1, no exception but break the string line when dump some special data

[WangLei1993]

when I use this lib to dumps some data, it make a puzzled question, sample.log is the minimized data to show it. my python version is 2.7.13 .

1. pyrapidjson 0.5 + not encode with utf-8

# -*- coding:utf-8 -*-
import codecs
import rapidjson
if __name__ == '__main__':
    with codecs.open('sample.log', 'rb', 'utf-8') as f_read:
        report_data = [f_read.read(),]
        print report_data
        report_json = rapidjson.dumps(report_data)
        print report_json

it raise a crash about python like:

2. pyrapidjson 0.5 + encode with utf-8

# -*- coding:utf-8 -*-
import codecs
import rapidjson
if __name__ == '__main__':
    with codecs.open('sample.log', 'rb', 'utf-8') as f_read:
        report_data = [f_read.read().encode('utf-8'),]
        print report_data
        report_json = rapidjson.dumps(report_data)
        print report_json

it may right like:

3. pyrapidjson 0.5.1 + not encode with utf-8

# -*- coding:utf-8 -*-
import codecs
import rapidjson
if __name__ == '__main__':
    with codecs.open('sample.log', 'rb', 'utf-8') as f_read:
        report_data = [f_read.read(),]
        print report_data
        report_json = rapidjson.dumps(report_data)
        print report_json

it like the following picture, no exception but break the string line:

4. pyrapidjson 0.5.1 + encode with utf-8

# -*- coding:utf-8 -*-
import codecs
import rapidjson
if __name__ == '__main__':
    with codecs.open('sample.log', 'rb', 'utf-8') as f_read:
        report_data = [f_read.read().encode('utf-8'),]
        print report_data
        report_json = rapidjson.dumps(report_data)
        print report_json

it like the following picture, also no exception but break the string line:

with this condition, I can't know right or not about dumps result. I think it may raise an exception when meet this condition or another way to let user know about this error.