Easy
You are climbing a staircase. It takes n steps to reach the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
Example 1:
Input: n = 2
Output: 2
Explanation: There are two ways to climb to the top.
1. 1 step + 1 step
2. 2 steps
Example 2:
Input: n = 3
Output: 3
Explanation: There are three ways to climb to the top.
1. 1 step + 1 step + 1 step
2. 1 step + 2 steps
3. 2 steps + 1 step
Constraints:
1 <= n <= 45
class Solution:
def climbStairs(self, n: int) -> int:
dp = {}
def helper(steps_left):
count = 0
if steps_left == 0:
return 1
if dp.get(steps_left) is not None:
return dp.get(steps_left)
if steps_left - 1 >= 0:
count += helper(steps_left - 1)
if steps_left - 2 >= 0:
count += helper(steps_left - 2)
dp[steps_left] = count
return dp[steps_left]
return helper(n)