-
Notifications
You must be signed in to change notification settings - Fork 0
/
24.两两交换链表中的节点.cpp
75 lines (72 loc) · 1.61 KB
/
24.两两交换链表中的节点.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
#include <vector>
#include <algorithm>
#include <stack>
#include <map>
#include <unordered_map>
#include <set>
#include <unordered_set>
#include <queue>
#include <deque>
#include <list>
#include <string>
using namespace std;
/*
* @lc app=leetcode.cn id=24 lang=cpp
*
* [24] 两两交换链表中的节点
*/
struct ListNode
{
int val;
ListNode *next;
ListNode() : val(0), next(nullptr) {}
ListNode(int x) : val(x), next(nullptr) {}
ListNode(int x, ListNode *next) : val(x), next(next) {}
};
// @lc code=start
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution
{
public:
ListNode *swapPairs(ListNode *head)
{
ListNode *vh = new ListNode(0xffff, head);
ListNode *pre = vh, *cur = head, *after = NULL;
if(cur == NULL)
{
return NULL;
}
if(cur->next == NULL)
{
return cur;
}
for(after = cur->next; after != NULL; after = after->next)
{
cur->next = after->next;
after->next = pre->next;
pre->next = after;
ListNode *tmp = after;
after = cur;
cur = after;
pre = after;
cur = after->next;
if(after->next != NULL)
{
after = after->next;
}
}
head = vh->next;
delete vh;
return head;
}
};
// @lc code=end