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701.二叉搜索树中的插入操作.cpp
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701.二叉搜索树中的插入操作.cpp
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#include <map>
#include <unordered_map>
#include <set>
#include <unordered_set>
#include <queue>
#include <stack>
#include <deque>
#include <list>
#include <string>
#include <algorithm>
#include <iterator>
#include <iostream>
using namespace std;
/*
* @lc app=leetcode.cn id=701 lang=cpp
*
* [701] 二叉搜索树中的插入操作
*/
struct TreeNode
{
int val;
TreeNode *left;
TreeNode *right;
TreeNode() : val(0), left(nullptr), right(nullptr) {}
TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
};
// @lc code=start
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
TreeNode* travel(TreeNode* root, int val) {
if (root == NULL) {
return new TreeNode(val);
}
if (root->val < val) {
root->right = travel(root->right, val);
}
if (root->val >= val) {
root->left= travel(root->left, val);
}
return root;
}
TreeNode* insertIntoBST(TreeNode* root, int val) {
return travel(root, val);
}
//迭代法
TreeNode* insertIntoBST_1(TreeNode* root, int val) {
if (root == NULL) {
return new TreeNode(val);
}
TreeNode* cur = root;
TreeNode* pre = NULL;
while (cur != NULL) {
pre = cur;
if (cur->val > val) {
cur = cur->left;
} else {
cur = cur->right;
}
}
TreeNode* tmp = new TreeNode(val);
if (pre->val > val) {
pre->left = tmp;
} else {
pre->right = tmp;
}
return root;
}
};
// @lc code=end
int main() {
Solution solution;
TreeNode* root = new TreeNode(4);
root->left = new TreeNode(2);
root->right = new TreeNode(7);
root->left->left = new TreeNode(1);
root->left->right = new TreeNode(3);
solution.insertIntoBST(root, 5);
cout<<root->right->left->val<<endl;
return 0;
}