1.md

Results of GPT-4 on HumanEval/1

Date: 18 July, 2023
Model: gpt-4
Temperature: 0.2
Passing runs: 6
Total runs: 10
Success rate: 60%

Prompt

Tokens: 141

from typing import List


def separate_paren_groups(paren_string: str) -> List[str]:
    """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
    separate those group into separate strings and return the list of those.
    Separate groups are balanced (each open brace is properly closed) and not nested within each other
    Ignore any spaces in the input string.
    >>> separate_paren_groups('( ) (( )) (( )( ))')
    ['()', '(())', '(()())']
    """

The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.

Correct solution

from typing import List


def separate_paren_groups(paren_string: str) -> List[str]:
    """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
    separate those group into separate strings and return the list of those.
    Separate groups are balanced (each open brace is properly closed) and not nested within each other
    Ignore any spaces in the input string.
    >>> separate_paren_groups('( ) (( )) (( )( ))')
    ['()', '(())', '(()())']
    """result = []
    current_string = []
    current_depth = 0

    for c in paren_string:
        if c == '(':
            current_depth += 1
            current_string.append(c)
        elif c == ')':
            current_depth -= 1
            current_string.append(c)

            if current_depth == 0:
                result.append(''.join(current_string))
                current_string.clear()

    return result

Unit tests

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}


def check(candidate):
    assert candidate('(()()) ((())) () ((())()())') == [
        '(()())', '((()))', '()', '((())()())'
    ]
    assert candidate('() (()) ((())) (((())))') == [
        '()', '(())', '((()))', '(((())))'
    ]
    assert candidate('(()(())((())))') == [
        '(()(())((())))'
    ]
    assert candidate('( ) (( )) (( )( ))') == ['()', '(())', '(()())']

Runs

❌ Run 1

Start time: 2023-07-18 18:58:48
Duration: 13.99s
Completion tokens: 195
Result: Fail

from typing import List


def separate_paren_groups(paren_string: str) -> List[str]:
    """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
    separate those group into separate strings and return the list of those.
    Separate groups are balanced (each open brace is properly closed) and not nested within each other
    Ignore any spaces in the input string.
    >>> separate_paren_groups('( ) (( )) (( )( ))')
    ['()', '(())', '(()())']
    """
    paren_string = paren_string.replace(' ', '')
    stack = []
    result = []
    group = ''
    for char in paren_string:
        if char == '(':
            if stack:
                group += char
            stack.append(char)
        elif char == ')':
            stack.pop()
            group += char
            if not stack:
                result.append(group)
                group = ''
    return result

✅ Run 2

Start time: 2023-07-18 18:58:31
Duration: 16.42s
Completion tokens: 204
Result: Pass

from typing import List

def separate_paren_groups(paren_string: str) -> List[str]:
    """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
    separate those group into separate strings and return the list of those.
    Separate groups are balanced (each open brace is properly closed) and not nested within each other
    Ignore any spaces in the input string.
    >>> separate_paren_groups('( ) (( )) (( )( ))')
    ['()', '(())', '(()())']
    """
    paren_string = paren_string.replace(' ', '')
    paren_groups = []
    start = 0
    balance = 0
    for i, char in enumerate(paren_string):
        if char == '(':
            balance += 1
        elif char == ')':
            balance -= 1
        if balance == 0:
            paren_groups.append(paren_string[start:i+1])
            start = i+1
    return paren_groups

✅ Run 3

Start time: 2023-07-18 18:58:18
Duration: 12.98s
Completion tokens: 197
Result: Pass

from typing import List


def separate_paren_groups(paren_string: str) -> List[str]:
    """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
    separate those group into separate strings and return the list of those.
    Separate groups are balanced (each open brace is properly closed) and not nested within each other
    Ignore any spaces in the input string.
    >>> separate_paren_groups('( ) (( )) (( )( ))')
    ['()', '(())', '(()())']
    """
    paren_string = paren_string.replace(" ", "")
    stack = []
    result = []
    group = ""
    for char in paren_string:
        if char == "(":
            if group and not stack:
                result.append(group)
                group = ""
            stack.append(char)
        elif char == ")":
            stack.pop()
        group += char
    if group:
        result.append(group)
    return result

✅ Run 4

Start time: 2023-07-18 18:58:02
Duration: 15.88s
Completion tokens: 209
Result: Pass

from typing import List

def separate_paren_groups(paren_string: str) -> List[str]:
    """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
    separate those group into separate strings and return the list of those.
    Separate groups are balanced (each open brace is properly closed) and not nested within each other
    Ignore any spaces in the input string.
    >>> separate_paren_groups('( ) (( )) (( )( ))')
    ['()', '(())', '(()())']
    """
    paren_string = paren_string.replace(' ', '')
    paren_groups = []
    start = 0
    balance = 0
    for i in range(len(paren_string)):
        if paren_string[i] == '(':
            balance += 1
        elif paren_string[i] == ')':
            balance -= 1
        if balance == 0:
            paren_groups.append(paren_string[start:i+1])
            start = i+1
    return paren_groups

✅ Run 5

Start time: 2023-07-18 18:57:51
Duration: 10.8s
Completion tokens: 204
Result: Pass

from typing import List


def separate_paren_groups(paren_string: str) -> List[str]:
    """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
    separate those group into separate strings and return the list of those.
    Separate groups are balanced (each open brace is properly closed) and not nested within each other
    Ignore any spaces in the input string.
    >>> separate_paren_groups('( ) (( )) (( )( ))')
    ['()', '(())', '(()())']
    """
    paren_string = paren_string.replace(" ", "")
    paren_groups = []
    start = 0
    balance = 0

    for i, char in enumerate(paren_string):
        if char == '(':
            balance += 1
        elif char == ')':
            balance -= 1
        if balance == 0:
            paren_groups.append(paren_string[start:i+1])
            start = i+1

    return paren_groups

❌ Run 6

Start time: 2023-07-18 18:57:35
Duration: 16.36s
Completion tokens: 195
Result: Fail

from typing import List


def separate_paren_groups(paren_string: str) -> List[str]:
    """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
    separate those group into separate strings and return the list of those.
    Separate groups are balanced (each open brace is properly closed) and not nested within each other
    Ignore any spaces in the input string.
    >>> separate_paren_groups('( ) (( )) (( )( ))')
    ['()', '(())', '(()())']
    """
    paren_string = paren_string.replace(' ', '')
    stack = []
    result = []
    group = ''
    for char in paren_string:
        if char == '(':
            if stack:
                group += char
            stack.append(char)
        elif char == ')':
            stack.pop()
            group += char
            if not stack:
                result.append(group)
                group = ''
    return result

✅ Run 7

Start time: 2023-07-18 18:57:20
Duration: 14.6s
Completion tokens: 218
Result: Pass

from typing import List

def separate_paren_groups(paren_string: str) -> List[str]:
    """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
    separate those group into separate strings and return the list of those.
    Separate groups are balanced (each open brace is properly closed) and not nested within each other
    Ignore any spaces in the input string.
    >>> separate_paren_groups('( ) (( )) (( )( ))')
    ['()', '(())', '(()())']
    """
    paren_string = paren_string.replace(" ", "")
    stack = []
    result = []
    for char in paren_string:
        if char == '(':
            stack.append(char)
        elif char == ')':
            temp = ''
            while stack and stack[-1] != '(':
                temp = stack.pop() + temp
            if stack:
                stack.pop()
            temp = '(' + temp + ')'
            if not stack:
                result.append(temp)
            else:
                stack.append(temp)
    return result

❌ Run 8

Start time: 2023-07-18 18:57:05
Duration: 15.23s
Completion tokens: 200
Result: Fail

from typing import List

def separate_paren_groups(paren_string: str) -> List[str]:
    """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
    separate those group into separate strings and return the list of those.
    Separate groups are balanced (each open brace is properly closed) and not nested within each other
    Ignore any spaces in the input string.
    >>> separate_paren_groups('( ) (( )) (( )( ))')
    ['()', '(())', '(()())']
    """
    paren_string = paren_string.replace(" ", "")
    stack = []
    result = []
    current_group = ""
    for char in paren_string:
        if char == '(':
            if stack:
                current_group += char
            stack.append(char)
        elif char == ')':
            stack.pop()
            current_group += char
            if not stack:
                result.append(current_group)
                current_group = ""
    return result

❌ Run 9

Start time: 2023-07-18 18:56:46
Duration: 18.86s
Completion tokens: 200
Result: Fail

from typing import List

def separate_paren_groups(paren_string: str) -> List[str]:
    """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
    separate those group into separate strings and return the list of those.
    Separate groups are balanced (each open brace is properly closed) and not nested within each other
    Ignore any spaces in the input string.
    >>> separate_paren_groups('( ) (( )) (( )( ))')
    ['()', '(())', '(()())']
    """
    paren_string = paren_string.replace(" ", "")
    stack = []
    result = []
    current_group = ""
    for char in paren_string:
        if char == '(':
            if stack:
                current_group += char
            stack.append(char)
        elif char == ')':
            stack.pop()
            current_group += char
            if not stack:
                result.append(current_group)
                current_group = ""
    return result

✅ Run 10

Start time: 2023-07-18 18:56:30
Duration: 15.67s
Completion tokens: 197
Result: Pass

from typing import List


def separate_paren_groups(paren_string: str) -> List[str]:
    """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
    separate those group into separate strings and return the list of those.
    Separate groups are balanced (each open brace is properly closed) and not nested within each other
    Ignore any spaces in the input string.
    >>> separate_paren_groups('( ) (( )) (( )( ))')
    ['()', '(())', '(()())']
    """
    paren_string = paren_string.replace(' ', '')
    result = []
    stack = []
    start = 0
    for i, char in enumerate(paren_string):
        if char == '(':
            if not stack:
                start = i
            stack.append(char)
        elif char == ')':
            stack.pop()
            if not stack:
                result.append(paren_string[start:i+1])
    return result