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Results of GPT-4 on HumanEval/113

Date: 18 July, 2023
Model: gpt-4
Temperature: 0.2
Passing runs: 10
Total runs: 10
Success rate: 100%

Prompt

Tokens: 199

def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """

The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.

Correct solution

def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """res = []
    for arr in lst:
        n = sum(int(d)%2==1 for d in arr)
        res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
    return res

Unit tests

def check(candidate):

    # Check some simple cases
    assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
    assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."], "Test 2"
    assert candidate(['271', '137', '314']) == [
        'the number of odd elements 2n the str2ng 2 of the 2nput.',
        'the number of odd elements 3n the str3ng 3 of the 3nput.',
        'the number of odd elements 2n the str2ng 2 of the 2nput.'
    ]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"

Runs

✅ Run 1

Start time: 2023-07-18 18:10:13
Duration: 18.64s
Completion tokens: 238
Result: Pass

def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    result = []
    for i in lst:
        count = sum(1 for digit in i if int(digit) % 2 != 0)
        result.append("the number of odd elements {}n the str{}ng {} of the {}nput.".format(count, count, count, count))
    return result

✅ Run 2

Start time: 2023-07-18 18:09:57
Duration: 16.21s
Completion tokens: 238
Result: Pass

def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    result = []
    for i in lst:
        count = sum(1 for digit in i if int(digit) % 2 != 0)
        result.append("the number of odd elements {}n the str{}ng {} of the {}nput.".format(count, count, count, count))
    return result

✅ Run 3

Start time: 2023-07-18 18:09:40
Duration: 16.78s
Completion tokens: 237
Result: Pass

def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    result = []
    for s in lst:
        count = sum(1 for c in s if int(c) % 2 != 0)
        result.append("the number of odd elements {}n the str{}ng {} of the {}nput.".format(count, count, count, count))
    return result

✅ Run 4

Start time: 2023-07-18 18:09:20
Duration: 20.13s
Completion tokens: 244
Result: Pass

def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    result = []
    for i in lst:
        odd_count = sum(1 for digit in i if int(digit) % 2 != 0)
        result.append("the number of odd elements {}n the str{}ng {} of the {}nput.".format(odd_count, odd_count, odd_count, odd_count))
    return result

✅ Run 5

Start time: 2023-07-18 18:08:59
Duration: 20.99s
Completion tokens: 238
Result: Pass

def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    result = []
    for i in lst:
        count = sum(1 for digit in i if int(digit) % 2 != 0)
        result.append("the number of odd elements {}n the str{}ng {} of the {}nput.".format(count, count, count, count))
    return result

✅ Run 6

Start time: 2023-07-18 18:08:36
Duration: 22.61s
Completion tokens: 243
Result: Pass

def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    result = []
    for s in lst:
        odd_count = sum(1 for c in s if int(c) % 2 == 1)
        result.append("the number of odd elements {}n the str{}ng {} of the {}nput.".format(odd_count, odd_count, odd_count, odd_count))
    return result

✅ Run 7

Start time: 2023-07-18 18:08:17
Duration: 19.79s
Completion tokens: 238
Result: Pass

def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    result = []
    for i in lst:
        count = sum(1 for digit in i if int(digit) % 2 != 0)
        result.append("the number of odd elements {}n the str{}ng {} of the {}nput.".format(count, count, count, count))
    return result

✅ Run 8

Start time: 2023-07-18 18:07:54
Duration: 22.26s
Completion tokens: 244
Result: Pass

def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    result = []
    for i in lst:
        odd_count = sum(1 for digit in i if int(digit) % 2 != 0)
        result.append("the number of odd elements {}n the str{}ng {} of the {}nput.".format(odd_count, odd_count, odd_count, odd_count))
    return result

✅ Run 9

Start time: 2023-07-18 18:07:37
Duration: 16.96s
Completion tokens: 238
Result: Pass

def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    result = []
    for i in lst:
        count = sum(1 for digit in i if int(digit) % 2 != 0)
        result.append("the number of odd elements {}n the str{}ng {} of the {}nput.".format(count, count, count, count))
    return result

✅ Run 10

Start time: 2023-07-18 18:07:14
Duration: 22.89s
Completion tokens: 238
Result: Pass

def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    result = []
    for i in lst:
        count = sum(1 for digit in i if int(digit) % 2 != 0)
        result.append("the number of odd elements {}n the str{}ng {} of the {}nput.".format(count, count, count, count))
    return result