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This won't compile (can't create the typeclass because of java.util.UUID. There are other examples, see #51 (comment), which was handled simply by changing the HashMap to a Map. In this case, it's not feasible.
For many code bases that uses UUID's for identity keys. Should we handle this case by manually registering a typeclass for this type? Something like:
Given the following
silly
rule, but just to illustrate:This won't compile (can't create the typeclass because of
java.util.UUID
. There are other examples, see #51 (comment), which was handled simply by changing theHashMap
to aMap
. In this case, it's not feasible.For many code bases that uses UUID's for identity keys. Should we handle this case by manually registering a typeclass for this type? Something like:
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