From 90baab073fa109debd8daaaa2bcc64084d8c2be0 Mon Sep 17 00:00:00 2001
From: Xiaokang2022 <2951256653@qq.com>
Date: Sun, 3 Nov 2024 12:52:17 +0800
Subject: [PATCH] style

---
 Doc/library/cmath.rst | 6 +++++-
 Doc/library/math.rst  | 8 +++++---
 2 files changed, 10 insertions(+), 4 deletions(-)

diff --git a/Doc/library/cmath.rst b/Doc/library/cmath.rst
index 17be747e3519c9..99f1b50d0d96ab 100644
--- a/Doc/library/cmath.rst
+++ b/Doc/library/cmath.rst
@@ -229,7 +229,11 @@ Classification functions
    tolerance is ``1e-09``, which assures that the two values are the same
    within about 9 decimal digits.  *rel_tol* must be greater than zero.
 
-   *abs_tol* is the absolute tolerance; it defaults to ``0.0`` and it must be nonnegative.  When comparing ``x`` to ``0.0``, ``isclose(x, 0)`` is computed as ``abs(x) <= rel_tol  * abs(x)``, which is false for any ``x`` and rel_tol less than ``1.0``.  So add an appropriate positive abs_tol argument to the call. 
+   *abs_tol* is the absolute tolerance; it defaults to ``0.0`` and it must be
+   nonnegative.  When comparing ``x`` to ``0.0``, ``isclose(x, 0)`` is computed
+   as ``abs(x) <= rel_tol  * abs(x)``, which is false for any ``x`` and rel_tol
+   less than ``1.0``.  So add an appropriate positive abs_tol argument to the
+   call. 
 
    If no errors occur, the result will be:
    ``abs(a-b) <= max(rel_tol * max(abs(a), abs(b)), abs_tol)``.
diff --git a/Doc/library/math.rst b/Doc/library/math.rst
index 396448ae8f3a66..e8fc959a1e242b 100644
--- a/Doc/library/math.rst
+++ b/Doc/library/math.rst
@@ -166,9 +166,11 @@ Number-theoretic and representation functions
    tolerance is ``1e-09``, which assures that the two values are the same
    within about 9 decimal digits.  *rel_tol* must be greater than zero.
 
-   *abs_tol* is the absolute tolerance; it must be nonnegative.  Only ``0.0``
-   is close to ``0.0`` per default.  Pass an appropriate absolute tolerance to
-   compare with ``0.0``.
+   *abs_tol* is the absolute tolerance; it defaults to ``0.0`` and it must be
+   nonnegative.  When comparing ``x`` to ``0.0``, ``isclose(x, 0)`` is computed
+   as ``abs(x) <= rel_tol  * abs(x)``, which is false for any ``x`` and rel_tol
+   less than ``1.0``.  So add an appropriate positive abs_tol argument to the
+   call. 
 
    If no errors occur, the result will be:
    ``abs(a-b) <= max(rel_tol * max(abs(a), abs(b)), abs_tol)``.