Is even and contains red - 3rd test

[johnylemony]

I run into an issue, where I cannot go do 3rd test.

My code is

def is_even_and_contains_red(a_list):
if "red" in a_list:
    if len(a_list) % 2 == 0:
        return True
else:
    return False

and error message is

tests.py:30: in test_odd_with_red
assert is_even_and_contains_red(['red', 'blue', 'green']) == False
E AssertionError: assert None == False
E + where None = is_even_and_contains_red(['red', 'blue', 'green'])

I follow it step by step, but still cannot figure out what I'm missing.
I don't mind if someone just could give me a hint. I do not need ready answer :)

[IAMTARA]

You have two If statements, but only one Else statement. The Else corresponds to the first If.

But there's nothing in your code to say what happens if your second if statement is False, so if len(a_list) is an odd number it's just going to spit the results of the first If statement.

[ajtran303]

johnylemony Here is what I came up with!

def is_even_and_contains_red(a_list):
if 'red' in a_list and len(a_list) % 2 == 0:
return True
else:
return False