Resolution of effect without subscription

[Solido]

effect(() => print("Startup"));

This effect will be resolved once and only once.

Is this expected as there is no subscription to it to respond too?

import 'package:signals/signals.dart';

void main() {
  effect(() {
    print("Startup");
  });
}

[rodydavis]

That is correct, it will only subscribe on signals in the block scope that call .value

[Solido]

To clarify the effect is only declared, subscribe to nothing yet trigger.
How is that done and is this expected?

[Solido]

Code added in first post for clarification

[jinyus]

The effect runs immediately, that's the only way for it know which signals were accessed...so it can start watching them.