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I need to define the conditional output, then created the function inside gulp.dest(). Thanks to vynil-named, we don't need to define the entry points, however to define the output condition, we need to know where file gotten from (it may be public or admin paths, for example).
Inside 'gulp.dest()', it says that file gotten from C:\MyIde\projects\testProj\someEntryPoint.js, however actually this file is in C:\MyIde\projects\testProj\source\public\js\someEntryPoint.js:
Before I ask "How to define desired output paths?", I need to understand what's going on. I defined the output paths for pug and sass by same way: nothing like this happened.
The text was updated successfully, but these errors were encountered:
ghost
changed the title
WebpackStream working with unexisting file
webpack-stream working with non-existent file
Nov 16, 2017
Curently, I use
webpack 3.4.1
andwebpack-stream 4.0.0
within next imports:I need to define the conditional output, then created the function inside
gulp.dest()
. Thanks tovynil-named
, we don't need to define the entry points, however to define the output condition, we need to know where file gotten from (it may bepublic
oradmin
paths, for example).Inside 'gulp.dest()', it says that file gotten from
C:\MyIde\projects\testProj\someEntryPoint.js
, however actually this file is inC:\MyIde\projects\testProj\source\public\js\someEntryPoint.js
:Before I ask "How to define desired output paths?", I need to understand what's going on. I defined the output paths for
pug
andsass
by same way: nothing like this happened.The text was updated successfully, but these errors were encountered: