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This issue is very high-quality; thanks for reporting it by reading the source code, @hilaryfrank! I hope you can learn by digging deeper and finally solving the problem.
异常错误
启动bot后。如果调用stop方法停止bot。此时会报错:Cannot read properties of undefined (reading 'start')。日志如下:
TypeError: Cannot read properties of undefined (reading 'start') at Wechat. (/Users/cdliuhaibo/bocai/learn/code/bocai/chatbot/node_modules/wechaty-puppet-wechat4u/src/puppet-wechat4u.ts:365:21) {stack: "TypeError: Cannot read properties of undefined (re…ty-puppet-wechat4u/src/puppet-wechat4u.ts:365:21)", message: "Cannot read properties of undefined (reading 'start')"}
根因分析
看了下源码,在puppet-wechat4u.ts中的如下代码this.wechat4u.start会报错:
原因应该是因为this.wechat4u这个对象为undefined。很好奇,在logout之后为什么还要调用 this.wechat4u.start()呢?
至于这里的this.wechat4u这个对象为undefined的原因,我大致看了下。是因为当我们调用stop方法的时候,会触发puppet-wechat4u.ts中的onStop方法。这个方法内容如下:
这里首先调用了this.wechat4u.stop(),然后就将就将this.wechat4u设置为了undefined。问题就在于this.wechat4u.stop()方法最终会触发logout操作。其代码如下(wecaht.js > stop):
这里触发了logout后,最终会触发一个logout事件。该事件会触发到puppet-wechat4u.ts中的logout监听(前面抛异常的位置)。代码如下,其中使用到了this.wechat4u,但这个对象已经在stop方法中被设置为undefined了。所以最终会报异常。
问题?
麻烦看下,
1、这个是问题还是我使用不对? 还是什么原因呢?
2、为什么logout后,还要启动一下wechat4u呢?
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