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Copy path19.删除链表的倒数第-n-个结点.swift
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19.删除链表的倒数第-n-个结点.swift
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/*
* @lc app=leetcode.cn id=19 lang=swift
*
* [19] 删除链表的倒数第 N 个结点
*/
// @lc code=start
/**
* Definition for singly-linked list.
* public class ListNode {
* public var val: Int
* public var next: ListNode?
* public init() { self.val = 0; self.next = nil; }
* public init(_ val: Int) { self.val = val; self.next = nil; }
* public init(_ val: Int, _ next: ListNode?) { self.val = val; self.next = next; }
* }
*/
class Solution {
// 空间换时间
// func removeNthFromEnd(_ head: ListNode?, _ n: Int) -> ListNode? {
// var items = [ListNode?]()
// var length = 0
// var index = head
// while index != nil {
// items.append(index!)
// length += 1
// index = index!.next
// }
// if length == 1 {
// return nil
// }
// let removedIndex = length - n
// if (removedIndex == 0){
// return items[1]
// }else if (removedIndex == length - 1) {
// items[removedIndex - 1]!.next = nil
// }else{
// items[removedIndex - 1]!.next = items[removedIndex + 1]
// }
// return items[0]
// }
// 快慢指针
func removeNthFromEnd(_ head: ListNode?, _ n: Int) -> ListNode? {
let tempNode = ListNode.init(0, head)
var slow: ListNode? = tempNode
var fast = head
for index in 0 ..< n {
fast = fast?.next
}
while fast != nil{
slow = slow?.next
fast = fast?.next
}
slow?.next = slow?.next?.next
return tempNode.next
}
}
// @lc code=end