Zmail allows you to send and get emails as possible as it can be in python.There is no need to check server address or make your own MIME object.With zmail, you only need to care about your mail content.
Zmail only running in python3 without third-party modules required. Do not support python2.
$ pip3 install zmail
or
$ pip install zmail
If that means your pip is also working for python3.
You can download the master branch of zmail,unzip it ,and do
$ python3 setup.py install
- Automatic looks for server address and it's port.
- Automatic use suitable protocol to login.
- Automatic converts a python dictionary to MIME object(with attachments).
- Automatic add mail header and local name to avoid server reject your mail.
- Easily custom your mail header.
- Only require python >= 3.5 , you can embed it in your project without other module required.
Before using it, please ensure:
- Using python3
- Open SMTP/POP3 function in your mail (For @163.com and @gmail.com you need to set your app private password)
Then, all you need to do is just import zmail.
import zmail
mail = {
'subject': 'Success!', # Anything you want.
'content': 'This message from zmail!', # Anything you want.
'attachments': '/Users/zyh/Documents/example.zip', # Absolute path will be better.
}
server = zmail.server('[email protected], 'yourpassword')
server.send_mail('[email protected]', mail)
server.send_mail(['[email protected]','[email protected]'], mail)
import zmail
server = zmail.server('[email protected], 'yourpassword')
mail = server.get_latest()
mail = server.get_mail(2)
mail = server.get_mails(subject='GitHub',after='2018-1-1',sender='github')
In the example, if 'GitHub' is in mail's subject, it will be matched, such as ' [GitHub] Your password has changed'
sender is the same way.
mail_info = server.get_info()
mailbox_info = server.stat()
The result is a tuple of 2 integers: (message count, mailbox size)
.
In zmail, all mails will be mapped to a python dictionary, you can access your mail by
subject = mail['subject']
Show you mail, use zmail.show()
import zmail
server = zmail.server('[email protected], 'yourpassword')
mail = server.get_latest()
zmail.show(mail)
Output, example :
content-type multipart/mixed
subject Success!
to zmail_user
from zmail<[email protected]>
date 2018-2-3 01:42:29 +0800
boundary ===============9196441298519098157==
content ['This message from zmail!']
contents [[b'Content-Type: text/plain; charset="utf-8"', b'MIME-Version: 1.0', b'Content-Transfer-Encoding: base64', b'', b'VGhpcyBtZXNzYWdlIGZyb20gem1haWwh', b'']]
attachments None
id 5
- content-type: Mail content type
- subject: Mail subject
- to
- from
- date: year-month-day time TimeZone
- boundary: If mail is multiple parts, you can get the boundary
- content: Mail content as text/plain
- contents: Mail's body as bytes,divided by boundary
- attachments: None or [['attachment-name;Encoding','ATTACHMENT-DATA']...]
- id: Mailbox id
import zmail
server = zmail.server('[email protected], 'yourpassword')
mail = server.get_latest()
zmail.get_attachment(mail)
you can rename your attachment file, by
zmail.get_attachment(mail,'example.zip')
The mail server in this list has been tested and approved.
If your mail server not in it, don't worry, zmail will handle it automatically.If there any problems in use, pls tell me in the Github.
Server address | Send mail | Retrieve mail | Remarks |
---|---|---|---|
@163.com | ✓ | ✓ | Need app private password |
@qq.com | ✓ | ✓ | POP3 need app private password |
@126.com | ✓ | ✓ | |
@yeah.net | ✓ | ✓ | |
@gmail.com | ✓ | ✓ | Need app private password |
@sina.com | ✓ | ✓ | |
@outlook | ✓ | ✓ |
server = zmail.server('user@example','password')
- server.send_mail([recipient,], mail)
- server.get_mail(which)
- server.get_mails(subject, sender, after, before)
- server.get_latest()
- server.get_info()
- server.stat()
- server.get_attachment(mail)
- zmail.show()