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Merge pull request #84 from prajwaln07/main
Implement GCD calculation using brute force, Euclidean, and binary me…
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#include <iostream> | ||
#include <algorithm> // For std::min | ||
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// Function to calculate GCD using brute force approach | ||
int calculateGCD_BruteForce(int firstNumber, int secondNumber) { | ||
int greatestCommonDivisor = 1; | ||
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for (int i = 1; i <= std::min(firstNumber, secondNumber); i++) { | ||
if (firstNumber % i == 0 && secondNumber % i == 0) { | ||
greatestCommonDivisor = i; | ||
} | ||
} | ||
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return greatestCommonDivisor; | ||
} | ||
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// Function to calculate GCD using Euclidean algorithm | ||
int calculateGCD_Euclidean(int firstNumber, int secondNumber) { | ||
while (secondNumber != 0) { | ||
int temp = secondNumber; | ||
secondNumber = firstNumber % secondNumber; | ||
firstNumber = temp; | ||
} | ||
return firstNumber; | ||
} | ||
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// Function to calculate GCD using Binary GCD (Stein's Algorithm) | ||
int calculateGCD_Binary(int firstNumber, int secondNumber) { | ||
if (firstNumber == 0) return secondNumber; | ||
if (secondNumber == 0) return firstNumber; | ||
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// Find the number of common factors of 2 | ||
int shift; | ||
for (shift = 0; ((firstNumber | secondNumber) & 1) == 0; ++shift) { | ||
firstNumber >>= 1; | ||
secondNumber >>= 1; | ||
} | ||
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// Make firstNumber odd | ||
while ((firstNumber & 1) == 0) { | ||
firstNumber >>= 1; | ||
} | ||
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// Apply the binary GCD algorithm | ||
do { | ||
while ((secondNumber & 1) == 0) { | ||
secondNumber >>= 1; | ||
} | ||
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if (firstNumber > secondNumber) { | ||
std::swap(firstNumber, secondNumber); | ||
} | ||
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secondNumber -= firstNumber; | ||
} while (secondNumber != 0); | ||
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return firstNumber << shift; // Restore the common factors of 2 | ||
} | ||
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int main() { | ||
int number1 = 36; | ||
int number2 = 60; | ||
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std::cout << "Brute Force GCD: " << calculateGCD_BruteForce(number1, number2) << std::endl; | ||
std::cout << "Euclidean GCD: " << calculateGCD_Euclidean(number1, number2) << std::endl; | ||
std::cout << "Binary GCD: " << calculateGCD_Binary(number1, number2) << std::endl; | ||
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return 0; | ||
} |