C++/Python FEniCS/dolfinx@aadf5fb

FEniCS · Oct 11, 2024 · 2dd808c · 2dd808c
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diff --git a/dolfinx/main/cpp/demos/demo_biharmonic.html b/dolfinx/main/cpp/demos/demo_biharmonic.html
@@ -136,8 +136,8 @@ <h3>Weak formulation<a class="headerlink" href="#weak-formulation" title="Link t
 \forall \ K \in \mathcal{T} \right\}
 \]</div>
 <p>and considering the boundary conditions</p>
-<div class="amsmath math notranslate nohighlight" id="equation-747fabe8-8a1c-4214-b7d9-8b88f33a0eb9">
-<span class="eqno">(1)<a class="headerlink" href="#equation-747fabe8-8a1c-4214-b7d9-8b88f33a0eb9" title="Permalink to this equation"></a></span>\[\begin{align}
+<div class="amsmath math notranslate nohighlight" id="equation-1ae86891-23be-4ba6-8b1c-84346d2775fc">
+<span class="eqno">(1)<a class="headerlink" href="#equation-1ae86891-23be-4ba6-8b1c-84346d2775fc" title="Permalink to this equation"></a></span>\[\begin{align}
 u &amp;= 0 \quad {\rm on} \ \partial\Omega, \\
 \nabla^{2} u &amp;= 0 \quad {\rm on} \ \partial\Omega,
 \end{align}\]</div>

diff --git a/...nx/main/python/_downloads/9561cf6cd1a70079b986f4eb31580cbd/demo_poisson_matrix_free.ipynb b/...nx/main/python/_downloads/9561cf6cd1a70079b986f4eb31580cbd/demo_poisson_matrix_free.ipynb
@@ -2,7 +2,7 @@
  "cells": [
   {
    "cell_type": "markdown",
-   "id": "213ca5e3",
+   "id": "717122c8",
    "metadata": {},
    "source": [
     "# Matrix-free conjugate gradient solver for the Poisson equation\n",
@@ -72,7 +72,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "2b34b2e6",
+   "id": "736d8e59",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -82,7 +82,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "7484d55b",
+   "id": "fd03657c",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -92,7 +92,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "c3292004",
+   "id": "75e85869",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -104,7 +104,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "7fa42c75",
+   "id": "8675095d",
    "metadata": {},
    "source": [
     "We begin by using {py:func}`create_rectangle\n",
@@ -117,7 +117,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "4b633860",
+   "id": "ee312c2d",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -130,7 +130,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "e33b3233",
+   "id": "a108163e",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -141,7 +141,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "da6208e2",
+   "id": "3a79af40",
    "metadata": {},
    "source": [
     "The second argument to {py:class}`functionspace\n",
@@ -160,7 +160,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "ff25f1d4",
+   "id": "d805b0b3",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -171,7 +171,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "0849b006",
+   "id": "442f80e3",
    "metadata": {},
    "source": [
     "We now find the degrees of freedom that are associated with the boundary\n",
@@ -182,7 +182,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "fad2b40e",
+   "id": "ae0753e2",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -191,7 +191,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "9b06033e",
+   "id": "c1e7c25e",
    "metadata": {},
    "source": [
     "and use {py:func}`dirichletbc <dolfinx.fem.dirichletbc>` to define the\n",
@@ -204,7 +204,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "660898a4",
+   "id": "3711b3f0",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -215,7 +215,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "893c50c4",
+   "id": "5caec983",
    "metadata": {},
    "source": [
     "Next, we express the variational problem using UFL."
@@ -224,7 +224,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "f9a13c21",
+   "id": "4d4266cd",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -239,7 +239,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "114e84f0",
+   "id": "4b2aa12c",
    "metadata": {},
    "source": [
     "For the matrix-free solvers we also define a second linear form `M` as\n",
@@ -255,7 +255,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "2e492db9",
+   "id": "c7d826cf",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -266,7 +266,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "f20418e8",
+   "id": "d7f50c20",
    "metadata": {},
    "source": [
     "### Matrix-free conjugate gradient solver\n",
@@ -280,7 +280,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "a17415cc",
+   "id": "141cc40b",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -295,7 +295,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "b69ddec2",
+   "id": "22794194",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -306,7 +306,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "88f0d15b",
+   "id": "a6a4403f",
    "metadata": {
     "lines_to_next_cell": 2
    },
@@ -318,7 +318,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "f2492737",
+   "id": "8a67d194",
    "metadata": {
     "lines_to_next_cell": 2
    },
@@ -341,7 +341,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "1af0980f",
+   "id": "020b2690",
    "metadata": {
     "lines_to_next_cell": 2
    },
@@ -357,7 +357,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "f9061136",
+   "id": "76b98ef4",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -403,7 +403,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "49f01091",
+   "id": "a14030d5",
    "metadata": {},
    "source": [
     "This matrix-free solver is now used to compute the finite element solution.\n",
@@ -414,7 +414,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "ffea570d",
+   "id": "c94d111b",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -426,7 +426,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "e0e66245",
+   "id": "065744f9",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -437,7 +437,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "57d7ea24",
+   "id": "c072995a",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -449,7 +449,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "3c0eb654",
+   "id": "1fae4987",
    "metadata": {},
    "outputs": [],
    "source": [

diff --git a/dolfinx/main/python/_downloads/9ed4657d08dda04de30e6463e2f58d75/demo_mixed-poisson.ipynb b/dolfinx/main/python/_downloads/9ed4657d08dda04de30e6463e2f58d75/demo_mixed-poisson.ipynb
@@ -2,15 +2,15 @@
  "cells": [
   {
    "cell_type": "markdown",
-   "id": "2c7616fb",
+   "id": "b2c6452d",
    "metadata": {},
    "source": [
     "# Mixed formulation for the Poisson equation"
    ]
   },
   {
    "cell_type": "markdown",
-   "id": "b744eafd",
+   "id": "81917cb5",
    "metadata": {},
    "source": [
     "This demo illustrates how to solve Poisson equation using a mixed\n",
@@ -22,7 +22,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "c5ad9fab",
+   "id": "4b3c0257",
    "metadata": {},
    "source": [
     "```{admonition} Download sources\n",
@@ -103,7 +103,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "49ed35cb",
+   "id": "c7ee98da",
    "metadata": {},
    "outputs": [],
    "source": [