Антон Белов home_work_2 #9
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Antol
approved these changes
Feb 24, 2022
| @@ -73,37 +73,44 @@ fun Shop.example(): Int? = customers.map { it.orders }.flatten().find { it.id == | |||
| //TODO | |||
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| //Преобразовать список клиентов в сет | |||
| fun Shop.getSetOfCustomers(): Set<Customer> = setOf() | |||
| fun Shop.getSetOfCustomers(): Set<Customer> = this.customers.toSet() | |||
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| // Вернуть список клиентов из представленного города | ||
| fun Shop.getCustomersFrom(city: City): List<Customer> = listOf() | ||
| fun Shop.getCustomersFrom(city: City): List<Customer> = | ||
| this.customers.filter { it.city == city }.toList() |
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| // Вернуть словарь в котором названия городов являются ключами, а значениями - сет клиентов, проживающих в этом городе | ||
| fun Shop.groupCustomersByCity(): Map<String, Set<Customer>> = mapOf() | ||
| fun Shop.groupCustomersByCity(): Map<String, Set<Customer>> = | ||
| this.customers.map { it.city.title to mutableSetOf(it) }.toMap() |
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Ошибка. У тебя всегда перезаписывается значение в словаре. То есть всегда только один клиент из города будет, даже если их на самом деле несколько
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| // Вернуть сет клиентов, у которых не доставленных заказов больше чем заказанных | ||
| fun Shop.getCustomersWithMoreUndeliveredOrdersThanDelivered(): Set<Customer> = setOf() | ||
| fun Shop.getCustomersWithMoreUndeliveredOrdersThanDelivered(): Set<Customer> = | ||
| this.customers.filter { it.orders.filter { !it.isDelivered }.size > it.orders.filter { it.isDelivered }.size } |
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.filter { !it.isDelivered }.size можно заменить на .count{ !it.isDelivered }
| fun Shop.getNumberOfTimesProductWasOrdered(product: Product): Int = | ||
| this.customers.map { it.orders.flatMap { it.products }.filter { it == product } }.size |
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та же история что и до этого, можно заменить на count с условием
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