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For p : ℚ⁺, there is r : ℚ⁺ with r + r < p (#1269) #8678

For p : ℚ⁺, there is r : ℚ⁺ with r + r < p (#1269)

For p : ℚ⁺, there is r : ℚ⁺ with r + r < p (#1269) #8678

typecheck (macOS-13, 2.7.0)

succeeded Feb 5, 2025 in 1m 37s