fix: return file protocol by default

pkg/utils/url.go

@@ -4,5 +4,8 @@ import "net/url"
 
 func ParseProtocol(uri string) (protocol string, err error) {
 	parsed, err := url.Parse(uri)
+	if parsed.Scheme == "" {
+		return "file", nil
+	}
 	return parsed.Scheme, err
 }

pkg/utils/url_test.go

@@ -0,0 +1,48 @@
+package utils_test
+
+import (
+	"testing"
+
+	"github.com/WangYihang/gojob/pkg/utils"
+)
+
+func TestParseProtocol(t *testing.T) {
+	testcases := []struct {
+		uri      string
+		expected string
+	}{
+		{
+			uri:      "http://example.com",
+			expected: "http",
+		},
+		{
+			uri:      "https://example.com",
+			expected: "https",
+		},
+		{
+			uri:      "ftp://example.com",
+			expected: "ftp",
+		},
+		{
+			uri:      "file://example.com",
+			expected: "file",
+		},
+		{
+			uri:      "s3://bucket/shakespeare.txt",
+			expected: "s3",
+		},
+		{
+			uri:      "/etc/passwd",
+			expected: "file",
+		},
+	}
+	for _, tc := range testcases {
+		protocol, err := utils.ParseProtocol(tc.uri)
+		if err != nil {
+			t.Errorf("unexpected error: %v", err)
+		}
+		if protocol != tc.expected {
+			t.Errorf("expected %s, got %s", tc.expected, protocol)
+		}
+	}
+}