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Update Misc/Practice/Practice.tex
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Co-authored-by: AoiYamada <[email protected]>
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ceciliachan1979 and AoiYamada authored Aug 2, 2024
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4 changes: 2 additions & 2 deletions Misc/Practice/Practice.tex
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Expand Up @@ -29,8 +29,8 @@ \subsubsection*{Solution}
p(x) - 1 &| (x + 1)^3 \\
p(x) - 1 &= (x + 1)^3(dx^2 + ex + f) \\
&= (x^3 + 3x^2 + 3x + 1)(dx^2 + ex + f) \\
&= dx^5 + (3d + e)x^4 + (3d + 3e + f)x^3 + (d + 3e + 3f)x^2 + (ex + 3f)x + f \\
p(x) &= dx^5 + (3d + e)x^4 + (3d + 3e + f)x^3 + (d + 3e + 3f)x^2 + (ex + 3f)x + (f + 1) \\
&= dx^5 + (3d + e)x^4 + (3d + 3e + f)x^3 + (d + 3e + 3f)x^2 + (e + 3f)x + f \\
p(x) &= dx^5 + (3d + e)x^4 + (3d + 3e + f)x^3 + (d + 3e + 3f)x^2 + (e + 3f)x + (f + 1) \\
\end{align*}

Match coefficients, we have:
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