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Intuitionize subgroups from df-subg to issubg2 #4684

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@jkingdon jkingdon commented Mar 2, 2025

The intuitionizing here is pretty easy for the most part. Only one theorem needs to be stated differently and of those proofs which need to change, it isn't in especially big ways.

jkingdon added 20 commits March 1, 2025 18:09
There is nothing called SubGroup so refer to SubGrp instead which is
what must have been meant.
This is all three syntaxes and df-subg , df-nsg , and df-eqg
Stated as in set.mm.  The proof needs some intuitionizing but is
basically the set.mm proof.
Restricting a group to its base set.
Stated as in set.mm.  The proof needs some intuitionizing but is
basically the set.mm proof.
Stated as in set.mm.  The proof needs some intuitionizing but is
basically the set.mm proof.
Stated as in set.mm.  The proof needs some intuitionizing but is
basically the set.mm proof.
Stated as in set.mm.  The proof needs a little bit of intuitionizing but
is basically the set.mm proof.
Stated as in set.mm.  The proof needs a little intuitionizing but is
basically the set.mm proof.
Stated as in set.mm.  The proof needs a little bit of intuitionizing but
is basically the set.mm proof.
This is ifeq2da from set.mm with a decidability condition added.  The
proof is based on the iset.mm proof of ifeq1dadc .

Correct comment for ifeq1dadc to reflect our conventions.
Stated as in set.mm.  The proof needs intuitionizing in several places
but is basically the set.mm proof.
This is issubg2 from set.mm with non-empty changed to inhabited.
The proof needs intuitionizing but is basically the set.mm proof.
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