core: set start job timeout from the kernel commandline (systemd#3112)

Add the boot parameter: systemd.default_timeout_start_sec to allow modification of the default start job timeout at boot time.
mohit84 · Apr 26, 2016 · 959718c · 959718c
1 parent a109d2e
commit 959718c
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diff --git a/man/kernel-command-line.xml b/man/kernel-command-line.xml
@@ -321,6 +321,15 @@
         </listitem>
       </varlistentry>
 
+      <varlistentry>
+        <term><varname>systemd.default_timeout_start_sec=</varname></term>
+
+        <listitem>
+          <para>Overwrites the default start job timeout <varname>DefaultTimeoutStartSec=</varname> at boot. For details,
+          see <citerefentry><refentrytitle>systemd-system.conf</refentrytitle><manvolnum>5</manvolnum></citerefentry>.</para>
+        </listitem>
+      </varlistentry>
+
       <varlistentry>
         <term><varname>modules-load=</varname></term>
         <term><varname>rd.modules-load=</varname></term>

diff --git a/src/core/main.c b/src/core/main.c
@@ -413,6 +413,15 @@ static int parse_proc_cmdline_item(const char *key, const char *value) {
                 target = runlevel_to_target(key);
                 if (target)
                         return free_and_strdup(&arg_default_unit, target);
+
+        } else if (streq(key, "systemd.default_timeout_start_sec") && value) {
+
+                r = parse_sec(value, &arg_default_timeout_start_usec);
+                if (r < 0)
+                        log_warning_errno(r, "Failed to parse default start timeout: %s, ignoring.", value);
+
+                if (arg_default_timeout_start_usec <= 0)
+                        arg_default_timeout_start_usec = USEC_INFINITY;
         }
 
         return 0;